140=4x^2+36x+72

Solution for 140=4x^2+36x+72 equation:

140=4x^2+36x+72

We move all terms to the left:

140-(4x^2+36x+72)=0

We get rid of parentheses

-4x^2-36x-72+140=0

We add all the numbers together, and all the variables

-4x^2-36x+68=0

a = -4; b = -36; c = +68;
Δ = b2-4ac
Δ = -362-4·(-4)·68
Δ = 2384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2384}=\sqrt{16*149}=\sqrt{16}*\sqrt{149}=4\sqrt{149}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{149}}{2*-4}=\frac{36-4\sqrt{149}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{149}}{2*-4}=\frac{36+4\sqrt{149}}{-8}
$